NCERT CLASS 6 | MATHEMATICS | GANITA PRAKASH
Chapter 10 – The Other Side of Zero
- Bela’s Building of Fun has the ground floor numbered 0. A child is on Floor +2 and presses the lift button –3. On which floor will the child reach?
A. +5
B. +1
C. –1
D. –5
Answer: C. –1 - Starting from Floor –1, Gurmit presses the +4 button. Which floor does he reach?
A. +3
B. +4
C. –3
D. –5
Answer: A. +3 - A visitor is on Floor +3. He presses –5 and then +2. Where does he reach?
A. +4
B. 0
C. –2
D. –4
Answer: B. 0 - Which expression represents moving from Floor +2 to Floor –5?
A. (+2) + (+7) = –5
B. (+2) + (–7) = –5
C. (–5) + (+7) = –2
D. (+2) – (–7) = –5
Answer: B. (+2) + (–7) = –5 - Basant accidentally presses +6 on the ground floor. Which button press will bring him back to Floor 0?
A. +6
B. –3
C. –6
D. +3
Answer: C. –6 - What is the additive inverse of –8?
A. –8
B. +8
C. 0
D. +16
Answer: B. +8 - The lift is at Floor –4. It moves up by 4 floors. Which expression gives the final floor?
A. (–4) + (+4) = 0
B. (–4) + (–4) = –8
C. (–4) – (+4) = –8
D. (+4) + (+4) = +8
Answer: A. (–4) + (+4) = 0 - A child is standing at Floor +4 and wants to reach Floor –2. Which button should the child press?
A. +6
B. +2
C. –2
D. –6
Answer: D. –6 - Which of the following correctly compares the floors –4 and –2?
A. –4 > –2
B. –4 < –2
C. –4 = –2
D. –2 < 0 < –4
Answer: B. –4 < –2 - In Bela’s Building of Fun, Jay is on Floor +2 and Aman is on Floor –3. Who is on the lower floor?
A. Jay
B. Aman
C. Both are on the same floor
D. Neither
Answer: B. Aman - A mineshaft has a level of –90 m. A lift moves down another 55 m. What is its new level?
A. –35 m
B. +145 m
C. –145 m
D. +35 m
Answer: C. –145 m - A mine worker is at level –90 m and wants to reach +40 m. What movement is required?
A. –130 m
B. +130 m
C. –50 m
D. +50 m
Answer: B. +130 m - A lift in a mine starts at +40 m and moves down to –50 m. What is the required movement?
A. +90 m
B. –90 m
C. +10 m
D. –10 m
Answer: B. –90 m - Evaluate the expression: (+4) + (–3) + (–2).
A. +3
B. +1
C. –1
D. –5
Answer: C. –1 - What is the value of (–1) + (+2) + (–3)?
A. +4
B. –2
C. +2
D. –4
Answer: B. –2 - A person starts at 9 on a number line and moves 6 steps backwards. Where does the person reach?
A. 15
B. 3
C. –3
D. –6
Answer: B. 3 - Starting from 3 on a number line, a person moves 5 steps backwards. What is the final position?
A. +8
B. +2
C. –2
D. –8
Answer: C. –2 - Which expression gives the movement needed to go from –2 to –1?
A. (–1) – (–2) = +1
B. (–2) – (–1) = +1
C. (–1) + (–2) = –3
D. (–1) – (+2) = –3
Answer: A. (–1) – (–2) = +1 - Evaluate: (+4) – (–3).
A. +1
B. –1
C. +7
D. –7
Answer: C. +7 - Which addition expression is equivalent to (+7) – (+5)?
A. (+7) + (+5)
B. (+7) + (–5)
C. (–7) + (+5)
D. (–7) + (–5)
Answer: B. (+7) + (–5) - Using the unmarked number line method, what is the value of 85 + (–60)?
A. 145
B. –145
C. 25
D. –25
Answer: C. 25 - Find the missing number: (–100) – (+250) = ?
A. +350
B. –350
C. +150
D. –150
Answer: B. –350 - Evaluate: –125 + (–30).
A. –95
B. +95
C. –155
D. +155
Answer: C. –155 - What is the value of +105 – (–55)?
A. +50
B. –50
C. +160
D. –160
Answer: C. +160 - A person has 5 positive tokens and 3 negative tokens. After cancelling zero pairs, how many positive tokens remain?
A. 8
B. 3
C. 2
D. 0
Answer: C. 2 - In the token model, what is the result of (+5) + (–8)?
A. +13
B. +3
C. –3
D. –13
Answer: C. –3 - A set contains 6 positive tokens and 4 positive tokens. What is its total value?
A. +2
B. +10
C. –10
D. –2
Answer: B. +10 - What is the result of (–3) + (–2) using negative tokens?
A. +5
B. –5
C. +1
D. –1
Answer: B. –5 - In the token model, what is the result of (+5) – (+6)?
A. +11
B. +1
C. –1
D. –11
Answer: C. –1 - To calculate (+4) – (–6) using tokens, how many zero pairs must be added to take away 6 negative tokens?
A. 2
B. 4
C. 6
D. 10
Answer: C. 6 - A person has ₹100 in a bank account and deposits ₹60. What is the new balance?
A. ₹40
B. ₹100
C. ₹160
D. –₹160
Answer: C. ₹160 - A bank account has ₹160. A person pays an electricity bill of ₹30. What is the remaining balance?
A. ₹190
B. ₹130
C. –₹130
D. –₹190
Answer: B. ₹130 - A person has ₹130 in an account and makes a purchase worth ₹150. What is the new balance?
A. ₹20
B. ₹280
C. –₹20
D. –₹280
Answer: C. –₹20 - A bank account starts at ₹0. It receives credits of ₹30, ₹40 and ₹50 and debits of ₹40, ₹50 and ₹60. What is the final balance?
A. ₹30
B. –₹30
C. ₹210
D. –₹210
Answer: B. –₹30 - A bank account starts at ₹0. The debits are ₹1, ₹2, ₹4, ₹8, ₹16, ₹32, ₹64 and ₹128. A credit of ₹256 is then received. What is the final balance?
A. ₹0
B. –₹255
C. +₹255
D. +₹128
Answer: A. ₹0 - A place is located 500 m below sea level. How should its height be represented?
A. +500 m
B. –500 m
C. 0 m
D. +50 m
Answer: B. –500 m - A mountain is 1500 m above sea level. Which integer represents its height?
A. –1500
B. 0
C. +1500
D. –150
Answer: C. +1500 - During a cold day in Leh, the temperature is –4°C. What does the negative sign indicate?
A. The temperature is 4°C above freezing
B. The temperature is 4°C below freezing
C. The temperature is 4°C above 0°C
D. The temperature is 4°C higher than 40°C
Answer: B. The temperature is 4°C below freezing - The temperature at one time is –4°C and later it becomes 8°C. By how many degrees has the temperature increased?
A. 4°C
B. 8°C
C. 12°C
D. 16°C
Answer: C. 12°C - In a hollow integer grid, the top row contains 5, –3 and –5. What is their sum, called the border sum?
A. +7
B. –3
C. –5
D. –8
Answer: B. –3 - A hollow integer grid has the left column 5, 0 and –8. What is its sum?
A. –13
B. –3
C. +3
D. +13
Answer: B. –3 - In the number-selection grid game, after choosing a number, which parts must be struck out?
A. Only the chosen number
B. Its row and its column
C. Only its row
D. All four corners
Answer: B. Its row and its column - Two dice have faces numbered –1, 2, –3, 4, –5 and 6. What is the smallest possible sum when both dice show their smallest values?
A. –5
B. –8
C. –10
D. +12
Answer: C. –10 - Using the same two dice, what is the largest possible sum?
A. +6
B. +10
C. +11
D. +12
Answer: D. +12 - Which of the following sums cannot be obtained by rolling the two dice described in the chapter?
A. –10
B. –8
C. +12
D. +11
Answer: D. +11 - Complete the sequence: –40, –34, –28, –22, ____, ____.
A. –18, –14
B. –16, –10
C. –20, –18
D. –14, –6
Answer: B. –16, –10 - Complete the sequence: 3, 4, 2, 5, 1, 6, 0, 7, ____, ____.
A. –1, 8
B. 8, –1
C. 1, 8
D. –2, 9
Answer: A. –1, 8 - Which ancient Indian mathematician gave explicit rules for operations involving positive numbers, negative numbers and zero in 628 CE?
A. Aryabhata
B. Brahmagupta
C. Kautilya
D. Bhaskara
Answer: B. Brahmagupta - In which mathematical work did Brahmagupta describe rules for positive numbers, negative numbers and zero?
A. Arthashastra
B. The Nine Chapters on Mathematical Art
C. Brāhma-sphuṭa-siddhānta
D. Bakśhālī manuscript
Answer: C. Brāhma-sphuṭa-siddhānta - According to the chapter, how were positive and negative numbers represented in the ancient Chinese mathematical work The Nine Chapters on Mathematical Art?
A. Using blue and yellow stones
B. Using red and black rods
C. Using circles and squares
D. Using green and red paper
Answer: B. Using red and black rods
- Chapter 1: Patterns in Mathematics MCQs
- Chapter 2: Lines and Angles MCQs
- Chapter 3: Number Play MCQs
- Chapter 4: Data Handling and Presentation MCQs
- Chapter 5: Prime Time MCQs
- Chapter 6: Perimeter and Area MCQs
- Chapter 7: Fractions MCQs
- Chapter 8: Playing with Constructions MCQs
- Chapter 9: Symmetry MCQs
- Chapter 10: The Other Side of Zero MCQs
